MATH SOLVE

4 months ago

Q:
# What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x = x = x = x = x =

Accepted Solution

A:

xΒ²+5x+5 has zeroes given by x=(-5Β±β25-20)/2=(-5Β±β5)/2=-1.3820 and -3.6180.

In simplest radical form the zeroes are -5/2+β5/2 and -5/2-β5/2.

In simplest radical form the zeroes are -5/2+β5/2 and -5/2-β5/2.